Massa es, m₁ = 36 g
kalor jenis es, c₁ = 0,5 kal / (g*°C)
kalor lebur, L₁ = 80 kal/g
suhu es, T₁ = -6°C
kapasitas kalor kalorimeter, C = 27 kal/°C
kalor jenis alkohol, c₂ = 0,58 kal/(g*°C)
suhu alkohol, T₂ = 50°C
suhu campuran, T' = 8°C
massa alkohol, m₂ = ?
Kalor lepas = Kalor terima
m₂ * c₂ * (T₂ - T') = m₁ * {c₁ * (0 - T₂) + L₁ + c air (T' - 0)} + C * (T' - T₁)
m₂ * 0,58 * 42 = 36 * {0,5*6 + 80 + 1*8} + 27 * 14
m₂ = 150 gram